std::ratio_divide
Defined in header <ratio>
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template< class R1, class R2 > using ratio_divide = /* see below */; |
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The alias template std::ratio_divide
denotes the result of dividing two exact rational fractions represented by the std::ratio specializations R1
and R2
.
The result is a std::ratio specialization std::ratio<U, V>, such that given Num == R1::num * R2::den and Denom == R1::den * R2::num (computed without arithmetic overflow), U
is std::ratio<Num, Denom>::num and V
is std::ratio<Num, Denom>::den.
[edit] Notes
If U
or V
is not representable in std::intmax_t
, the program is ill-formed. If Num
or Denom
is not representable in std::intmax_t
, the program is ill-formed unless the implementation yields correct values for U
and V
.
The above definition requires that the result of std::ratio_divide<R1, R2> be already reduced to lowest terms; for example, std::ratio_divide<std::ratio<1, 12>, std::ratio<1, 6>> is the same type as std::ratio<1, 2>.
[edit] Example
#include <iostream> #include <ratio> int main() { typedef std::ratio<2, 3> two_third; typedef std::ratio<1, 6> one_sixth; typedef std::ratio_divide<two_third, one_sixth> r; std::cout << "2/3 / 1/6 = " << r::num << '/' << r::den << '\n'; }
Output:
2/3 / 1/6 = 4/1