std::auto_ptr::auto_ptr
From cppreference.com
explicit auto_ptr( X* p = 0 ); |
(1) | (deprecated) |
auto_ptr( auto_ptr& r ); |
(2) | (deprecated) |
template< class Y > auto_ptr( auto_ptr<Y>& r ); |
(3) | (deprecated) |
template< class Y > auto_ptr( auto_ptr_ref<Y> m ); |
(4) | (deprecated) |
Constructs the auto_ptr
from a pointer that refers to the object to manage.
1) Constructs the
auto_ptr
with pointer p
.2) Constructs the
auto_ptr
with the pointer held in r
. r.release() is called to acquire the ownership of the object.3) Same as (2). Y* must be implicitly convertible to T*.
4) Constructs the
auto_ptr
with the pointer held in the auto_ptr
instance referred to by m
. p.release() is called for the auto_ptr p
that m
holds to acquire the ownership of the object. auto_ptr_ref
is an implementation-defined type that holds a reference to auto_ptr
. std::auto_ptr is implicitly convertible to and assignable from this type. The implementation is allowed to provide the template with a different name or implement equivalent functionality in other ways.[edit] Parameters
p | - | a pointer to an object to manage |
r | - | another auto_ptr to transfer the ownership of the object from
|
m | - | an implementation-defined type that holds a reference to auto_ptr
|
[edit] Exceptions
(none)
[edit] Notes
The constructor and the copy assignment operator from auto_ptr_ref
is provided to allow copy-constructing and assigning std::auto_ptr from nameless temporaries. Since its copy constructor and copy assignment operator take the argument as non-const reference, they cannot bind rvalue arguments directly. However, a user-defined conversion can be executed (which releases the original auto_ptr), followed by a call to the constructor or copy-assignment operator that take auto_ptr_ref
by value. This is an early implementation of move semantics.