std::experimental::make_array
From cppreference.com
< cpp | experimental
Defined in header <experimental/array>
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template <class D = void, class... Types> constexpr std::array<VT /* see below */, sizeof...(Types)> make_array(Types&&... t); |
(library fundamentals TS v2) | |
Creates a std::array whose size is equal to the number of arguments and whose elements are initialized from the corresponding arguments. Returns std::array<VT, sizeof...(Types)>{std::forward<Types>(t)...}
If D
is void, then the deduced type VT
is std::common_type_t<Types...>. Otherwise, it is D
.
If D
is void and any of std::decay_t<Types>... is a specialization of std::reference_wrapper, the program is ill-formed.
[edit] Possible implementation
namespace details { template<class> struct is_ref_wrapper : std::false_type {}; template<class T> struct is_ref_wrapper<std::reference_wrapper<T>> : std::true_type {}; template<class T> using not_ref_wrapper = std::experimental::negation<is_ref_wrapper<std::decay_t<T>>>; template <class D, class...> struct return_type_helper { using type = D; }; template <class... Types> struct return_type_helper<void, Types...> { static_assert(std::experimental::conjunction_v<not_ref_wrapper<Types>...>, "Types cannot contain reference_wrappers when D is void"); using type = std::common_type_t<Types...>; }; template <class D, class... Types> using return_type = std::array<typename return_type_helper<D, Types...>::type, sizeof...(Types)>; } template < class D = void, class... Types> constexpr details::return_type<D, Types...> make_array(Types&&... t) { return {std::forward<Types>(t)... }; } |
[edit] Example
This section is incomplete Reason: no example |
[edit] See also
Creates a std::array object from a built-in array (function template) |