std::experimental::filesystem::path::root_name
From cppreference.com
< cpp | experimental | fs | path
path root_name() const; |
(filesystem TS) | |
Returns the root name of the path. If the path does not include root name, returns path().
Contents |
[edit] Parameters
(none)
[edit] Return value
The root name of the path.
[edit] Exceptions
(none)
[edit] Example
Run this code
#include <iostream> #include <experimental/filesystem> namespace fs = std::experimental::filesystem; int main() { std::cout << "Current root name is: " << fs::current_path().root_name() << '\n'; }
Possible output:
Current root name is: "C:"
[edit] See also
returns the root directory of the path, if present (public member function) | |
returns the root path of the path, if present (public member function) |