I don't think so. s%HZ has to be less than HZ. Then
dividing that by HZ should result in zero. Where is my
thinking flawed?
>
> Though it might be easier to say (1000 * t) / HZ, now that I think about
> it.
That overflows... As does the other if HZ is less than
1000....
>
> --
> Vojtech Pavlik
> SuSE Labs
> -
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