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aligned_alloc

From cppreference.com
< c‎ | memory
Defined in header <stdlib.h>
void *aligned_alloc( size_t alignment, size_t size );
(since C11)

Allocate size bytes of uninitialized storage whose alignment is specified by alignment. The size parameter must be an integral multiple of alignment.

aligned_alloc is thread-safe: it behaves as though only accessing the memory locations visible through its argument, and not any static storage.

A previous call to free or realloc that deallocates a region of memory synchronizes-with a call to aligned_alloc that allocates the same or a part of the same region of memory. This synchronization occurs after any access to the memory by the deallocating function and before any access to the memory by aligned_alloc. There is a single total order of all allocation and deallocation functions operating on each particular region of memory.

Contents

[edit] Parameters

alignment - specifies the alignment. Must be a valid alignment supported by the implementation.
size - number of bytes to allocate. An integral multiple of alignment

[edit] Return value

On success, returns the pointer to the beginning of newly allocated memory. The returned pointer must be deallocated with free() or realloc().

On failure, returns a null pointer.

[edit] Notes

Passing a size which is not an integral multiple of alignment or a alignment which is not valid or not supported by the implementation causes the function to fail and return a null pointer (C11, as published, specified undefined behavior in this case, this was corrected by DR 460).

As an example of the "supported by the implementation" requriement, POSIX function posix_memalign accepts any alignment that is a power of two and a multiple of sizeof(void *), and POSIX-based implementations of aligned_alloc inherit this requirements.

Regular malloc aligns memory suitable for any object type (which, in practice, means that it is aligned to alignof(max_align_t)). This function is useful for over-aligned allocations, such as to SSE, cache line, or VM page boundary.

[edit] Example

#include <stdio.h>
#include <stdlib.h>
 
int main(void)
{
    int *p1 = malloc(10*sizeof *p1);
    printf("default-aligned addr:   %p\n", (void*)p1);
    free(p1);
 
    int *p2 = aligned_alloc(1024, 10*sizeof *p2);
    printf("1024-byte aligned addr: %p\n", (void*)p2);
    free(p2);
}

Possible output:

default-aligned addr:   0x17d6010
1024-byte aligned addr: 0x17d6400

[edit] References

  • C11 standard (ISO/IEC 9899:2011):
  • 7.22.3.1 The aligned_alloc function (p: 347-348)

[edit] See also

C++ documentation for aligned storage