sizeof operator
Queries size of the object or type
Used when actual size of the object must be known
Contents |
[edit] Syntax
sizeof( type )
|
(1) | ||||||||
sizeof expression |
(2) | ||||||||
Both versions return a value of type size_t.
[edit] Explanation
[edit] Notes
Depending on the computer architecture, a byte may consist of 8 or more bits, the exact number provided as CHAR_BIT.
sizeof(char), sizeof(signed char), and sizeof(unsigned char) always return 1.
sizeof cannot be used with function types, incomplete types (including void), or bit field lvalues.
When applied to an operand that has structure or union type, the result is the total number of bytes in such an object, including internal and trailing padding. The trailing padding is such that if the object were an element of an array, the alignment requirement of the next element of this array would be satisfied, in other words, sizeof(T) returns the size of an element of a T[] array.
Except if the type of expression is a VLA, (since C99)expression is not evaluated and the sizeof operator may be used in an integer constant expression.
| If the type of expression is a variable-length array type, expression is evaluated and the size of the array it evaluates to is calculated at run time. | (since C99) |
Number of elements in any array a including VLA (since C99) may be determined with the expression sizeof a / sizeof a[0]. Note that if a has pointer type (such as after array-to-pointer conversion of function parameter type adjustment), this expression would simply divide the number of bytes in a pointer type by the number of bytes in the pointed type.
[edit] Keywords
[edit] Example
sample output corresponds to a platform with 64-bit pointers and 32-bit int
#include <stdio.h> int main(void) { // type argument: printf("sizeof(float) = %zu\n", sizeof(float)); printf("sizeof(void(*)(void)) = %zu\n", sizeof(void(*)(void))); printf("sizeof(char[10]) = %zu\n", sizeof(char[10])); // printf("sizeof(void(void)) = %zu\n", sizeof(void(void))); // Error: function type // printf("sizeof(char[]) = %zu\n", sizeof(char[])); // Error: incomplete type // expression argument: printf("sizeof 'a' = %zu\n", sizeof 'a'); // type of 'a' is int // printf("sizeof main = %zu\n", sizeof main); // Error: Function type printf("sizeof &main = %zu\n", sizeof &main); printf("sizeof \"hello\" = %zu\n", sizeof "hello"); // type is char[6] }
Possible output:
sizeof(float) = 4 sizeof(void(*)(void)) = 8 sizeof(char[10]) = 10 sizeof 'a' = 4 sizeof &main = 8 sizeof "hello" = 6
[edit] References
- C11 standard (ISO/IEC 9899:2011):
- 6.5.3.4 The sizeof and _Alignof operators (p: 90-91)
- C99 standard (ISO/IEC 9899:1999):
- 6.5.3.4 The sizeof operator (p: 80-81)
- C89/C90 standard (ISO/IEC 9899:1990):
- 3.3.3.4 The sizeof operator
[edit] See also
| C++ documentation for sizeof operator
|
