free_irq

Russell King (rmk@arm.linux.org.uk)
Sun, 29 Sep 2002 14:15:50 +0100


Hi,

The comments surrounding free_irq() include these line:

* On a shared IRQ the caller must ensure the interrupt is disabled
* on the card it drives before calling this function. The function
* does not return until any executing interrupts for this IRQ
* have completed.
*
* This function may be called from interrupt context.

This last line is quite bogus.

- if we call this function to free IRQ "n" from an interrupt handler
running on IRQ "n", then we will deadlock; we call synchronize_irq(n)
which will wait for us to exit.

- if we call this function to free IRQ "n" from an interrupt handler
running on IRQ "b", and a handler for IRQ "n" is already running and
IRQ "n" interrupted IRQ "n", then we will deadlock.

In light of the above, I'd suggest changing the last line to:

* This function must not be called from interrupt context.

This patch is against 2.5.34:

--- orig/arch/i386/kernel/irq.c Fri Aug 30 14:52:51 2002
+++ linux/arch/i386/kernel/irq.c Sun Sep 29 14:13:39 2002
@@ -483,10 +483,7 @@
* does not return until any executing interrupts for this IRQ
* have completed.
*
- * This function may be called from interrupt context.
- *
- * Bugs: Attempting to free an irq in a handler for the same irq hangs
- * the machine.
+ * This function must not be called from interrupt context.
*/

void free_irq(unsigned int irq, void *dev_id)

-- 
Russell King (rmk@arm.linux.org.uk)                The developer of ARM Linux
             http://www.arm.linux.org.uk/personal/aboutme.html

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