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> In a transport protocol I'm implementing, I've adapted this TCP hashing
> function:
>
> static __inline__ int dcp_hashfn(__u32 laddr, __u16 lport,
> __u32 faddr, __u16 fport)
> {
> int h = ((laddr ^ lport) ^ (faddr ^ fport));
> h ^= h>>16;
> h ^= h>>8;
> /* make it always < size : */
> return h & (MY_HTABLE_SIZE - 1); /* MY_HT... = 128 */
> }
>
> Although I am treating it as a blackbox and it works fine for me, my
> professor pointed the following about this function:
If you're a student, you should probably try to figure
this out for yourself; it's the only way to learn.
> [...]
> If both IP addresses have the same upper 16 bits (like 155.246.10.5 and
> 155.246.120.30), then the 1st 4-way XOR will put 16 bits of zero in h.
> Then "h ^= h>>16" will preserve the upper 16 bits as zero. Then
> "h ^= h>>8" will preserve the upper 24 bits!
> [...]
This comment makes an assumption about the architecture
of the machine, and the way IP addresses are stored
into __u32s.
Consider the following code fragment:
printf("%x %x\n",
inet_addr("1.0.0.0"),
inet_addr("0.0.0.1"));
-neil
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