Wrong.
> Such a situation should be generated by code like this:
>
> iopl(3);
> ioperm (0,0x1f,1); /* 0x20-0x3ff remain masked */
> c = inb (0x20);
>
> However on my machine this codse is successful! How is that possible?
Because you have misunderstood how IOPL works.
-hpa
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