I'm confused because it looks to me as though it's still in KB,
but people say that devices can be up to 8 or 16TB, and there's
not enough room for that within a signed int containing KB
(2^31 * 2^10 = 2^41 = 2TB).
Either the rumour is true and it's in blocks, or the rumour
is false and it's in KB.
Clue, please!
Peter
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