Re: how to get cpu_khz?

[John Weber]

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David Fries wrote:
> 
> I'm using the TSC of the Pentium processors to get some precise timing
> delays for writing to a eeprom (bit banging bus operations), and it
> works just fine, but the cpu_khz variable isn't exported to a kernel
> module, so I hardcoded in my module.  It works fine for that one
> system, but obviously I don't want to hard code it for the general
> case.  I guess I could write my own routine to figure out what the
> cpu_khz is, but it is already done, so how do I get access to it?

I don't know of any official way of doing this, but here's some 
code (written by aa) that accomplishes this.
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/*
 *  $Id: MHz.c,v 1.4 2001/05/21 18:58:01 davej Exp $
 *  This file is part of x86info.
 *  (C) 2001 Dave Jones.
 *
 *  Licensed under the terms of the GNU GPL License version 2.
 *
 * Estimate CPU MHz routine by Andrea Arcangeli <[e-mail]>
 * Small changes by David Sterba <[e-mail]>
 *
 */

#include <stdio.h>
#include <sys/time.h>
#include <string.h>
#include <unistd.h>

__inline__ unsigned long long int rdtsc()
{
	unsigned long long int x;
	__asm__ volatile (".byte 0x0f, 0x31" : "=A" (x));
	return x;
}

void estimate_MHz()
{
	struct timezone tz;
        struct timeval tvstart, tvstop;
        unsigned long long int cycles[2]; /* gotta be 64 bit */
	unsigned int microseconds; /* total time taken */
	
	memset(&tz, 0, sizeof(tz));

	/* get this function in cached memory */
	gettimeofday(&tvstart, &tz);
	cycles[0] = rdtsc();
	gettimeofday(&tvstart, &tz);

	/* we don't trust that this is any specific length of time */
	usleep(1000000);
	
	cycles[1] = rdtsc();
	gettimeofday(&tvstop, &tz);
	microseconds = ((tvstop.tv_sec-tvstart.tv_sec)*1000000) +
		(tvstop.tv_usec-tvstart.tv_usec);

	printf("%lldMHz processor (estimate).\n",
		(cycles[1]-cycles[0])/microseconds);
}

int main(void)
{
	while (1) {
		estimate_MHz();
	}
	return (0);
}

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