Re: Setting up MTRRs for 4096MB RAM
H. Peter Anvin (hpa@zytor.com)
9 Aug 2001 10:53:00 -0700
Followup to: <Pine.LNX.4.21.0108091306550.18150-100000@willow.commerce.uk.net>
By author: Corin Hartland-Swann <cdhs@commerce.uk.net>
In newsgroup: linux.dev.kernel
>
> I am trying to set up a machine using the Tyan Tiger LE motherboard, and
> ServerWorks III LE chipset to use 4096MB RAM. I'm using kernel 2.4.7 with
> CONFIG_HIGHMEM4G.
>
> I know that I have to set the MTRR's up to extend the cacheable memory
> area, but can't work out how to set it up.
>
> I tried the following:
>
> # echo "disable=1" >| /proc/mtrr
> # echo "disable=0" >| /proc/mtrr
> # echo "base=0x0 size=0xFFFFFFFF type=write-back" >| /proc/mtrr
> mtrr: size and base must be multiples of 4 kiB
> mtrr: size: 0xffffffff base: 0x0
>
> Which doesn't make any sense. So I tried for 3G RAM:
>
> # echo "base=0x0 size=0xC0000000 type=write-back" >| /proc/mtrr
> mtrr: base(0x0000) is not aligned on a size(0xc0000000) boundary
>
> And then for 2G RAM:
>
> # echo "base=0x0 size=0x80000000 type=write-back" >| /proc/mtrr
>
> Which works perfectly. What gives?
>
Intel MTRRs have to be a multiple of 2, so you'd need 2 MTRRs if you
wanted to cover 3 GB. 0x80000000 is a multiple of 2; 0xC0000000
isn't, and 0xFFFFFFFF definitely isn't, although 0x100000000 is.
I'm surprised you didn't see that very pattern in your own responses:
you are entering the full size in the working case, but then subtract
1 in the 4 GB case.
-hpa
--
<hpa@transmeta.com> at work, <hpa@zytor.com> in private!
"Unix gives you enough rope to shoot yourself in the foot."
http://www.zytor.com/~hpa/puzzle.txt <amsp@zytor.com>
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