Imagine a macro of several lines of code like:
#define FOO(x) \
printf("arg is %s\n", x); \
do_something_useful(x);
Now imagine using it like:
if (blah == 2)
FOO(blah);
This interprets to
if (blah == 2)
printf("arg is %s\n", blah);
do_something_useful(blah);;
As you can see, the "if" then only encompasses the printf, and the
do_something_useful() call is unconditional (not within the scope of the
if), like you wanted it.
So, by using a block like do{...}while(0), you would get this:
if (blah == 2)
do {
printf("arg is %s\n", blah);
do_something_useful(blah);
} while (0);
Which is exactly what you want.
-- -----------=======-=-======-=========-----------=====------------=-=------ / Ben Collins -- ...on that fantastic voyage... -- Debian GNU/Linux \ ` bcollins@debian.org -- bcollins@openldap.org -- bcollins@linux.com ' `---=========------=======-------------=-=-----=-===-======-------=--=---' - To unsubscribe from this list: send the line "unsubscribe linux-kernel" in the body of a message to majordomo@vger.kernel.org More majordomo info at http://vger.kernel.org/majordomo-info.html Please read the FAQ at http://www.tux.org/lkml/